What has to be added to x2+3x−8 to get x2+x+6?
3 - 8
- 2x + 14
x + 6
2x + 14
Let the term which is to be added to x2+3x−8 be P.
⟹P=(x2+x+6)−(x2+3x−8) =x2+x+6−x2−3x+8 =−2x+14 So, −2x+14 is to be added to (\x^2 + 3x - 8\) to get (\x^2 + x + 6\).
What should be added to x2+3x−8 to get x2+x+6?
What must be added to(x3+3x−8) to get (3x3+x2+6)?