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Oxidizing Nature of Sulphuric Acid

What is an ox...

Question

What is an oxidizing agent in $C l_{2} + 2 I^{- 1} \to 2 C l^{-} + I_{2}$ ?

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Solution

Oxidising agent = oxidise another reactant (makes it lose electron) and is itself reduced (gains electron).
So $C l_{2}$ gains 2 electrons to become 2 $2 C l^{-} 1$ so it has been reduced. At the same time, it has taken these 2 electron from $2 I^{-}$ to oxidise it to $I_{2}$ .
Therefore the $C l$ is the oxidising agent as it forced the $2 I^{-}$ to lose electron,and gained 2 electron itself. $2 I^{-}$ is the reducing agent.

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Q. Which substance/ion is oxidised and which substance/ion is reduced in the following reaction?

2 I^{-} + C l_{2} \to 2 C l^{-} + I_{2}

Q. In the reaction of Cl₂ + 2KI -> 2KCl + I₂ the conversion of 2I to I₂ is deemed as _____ [OXIDATION / REDUCTION]

Which is a better oxidizing agent cl2 or f2

{C l}_{2} + 2 I^{-} \to I_{2} + 2 {C l}^{-}

The initial concentration of

I^{-}

0.25 m o l

L^{- 1}

and the concentration after

10

0.23 m o l

L^{- 1}

. Calculate the rate of disappearance of

I^{-}

and appearance of

I_{2}

Q. For the reaction,

C l_{2} + 2 I^{-} \to I_{2} + 2 C l^{-}

, the initial concentration of

I^{-}

0.20 m o l l i t^{- 1}

and the concentration after

20

0.18 m o l l i t^{- 1}

. Then, the rate of formation of

I_{2}

m o l l i t^{- 1} m i n^{- 1}

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