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Emulsions

what is dimer...

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what is dimeriation and trimerisation?

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Q. Acetic acid forms a dimer in the gas phase

The dimer is held together by two hydrogen bonds with a total strength of 66.5 kJ per mole of dimer. At

25^{o} C,

the equilibrium constant for the dimerisation is

1.3 \times 10^{3}

(pressure in atm). What is magnitude

△ S^{0}

for the reaction? Assume that

△ H

does not vary with temperature.

Q. The rate of formation of a dimer in a second order dimerisation reaction is

9.1 \times 10^{- 6} m o l L^{- 1} s^{- 1}

0.01 m o l L^{- 1}

monomer concentration. What will be the rate constant for the reaction?

Q. The freezing point of a solution of acetic acid (mole fraction =

0.02

) in benzene is

277.4 K

. Acetic acid exists partly as a dimer

2 A ⇌ A_{2} .

Determine the equilibrium constant for dimerisation. Freezing point of benzene is

278.4 K

K_{f}

5

.

Q. The freezing point of

0.02

mole fraction of acetic acid in benzene is

277.4

K. Acetic acid exists partly as dimer. Calculate the equilibrium constant for dimerisation. Freezing point of benzene is

278.4

K and heat of fusion of benzene is

10.042

^{- 1}

.

Q. The freezing point of

0.02 m o l

fraction solution of acetic acid

(A)

(B)

277.4 K

. Acetic acid exists partly as a dimer

2 A = A_{2}

. Calculate equilibrium constant for the dimerisation. Freezing point of benzene is

278.4 K

and its heat of fusion

Δ H_{f}

10.042 k J m o l^{- 1}

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