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Question

What is lnxxdx equal to ?

A
(lnx)22+c where c is the constant of integration
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B
(lnx)2+c where c is the constant of integration
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C
(lnx)2+c where c is the constant of integration
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D
None of the above
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Solution

The correct option is B (lnx)22+c where c is the constant of integration
Let I=lnxxdx
Put lnx=t dxx=dt
Then, we get
I=tdt=t22+c=(lnx)22+c
Hence, A is correct.

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