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Question

What is (xcosx+sinx)dx equal to?

Where c is an arbitrary constant

A
xsinx+c
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B
xcosx+c
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C
xsinx+c
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D
xcosx+c
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Solution

The correct option is A xsinx+c
(x.cosx+sinx)dx
=x.cosx.dx+sinx.dx
By u\sin g uv rule for integration in the first integral taking x as first function and \cos x as second we have,
=x.sinxsinx.dx+sinx.dx+c
=x.sinx+c
Hence, A is correct.

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