What is E-red for the reaction- Cu2- - 2e- - Cu in the half cell Pts2- - CUS - Cu if E-Cu2- - Cu is 0-34 and Ksp of CuS - 10-35-

The correct option is A 0.6925 V As we know, E_s^2 | CUS | Cu = E^⊖_Cu^2+ | Cu + 0.0592 log K_sp CuS = 0.34 + 0.0592 log 10^ 35 = ...

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What is E⊖r...

Question

What is $E_{r e d}^{⊖}$ for the reaction; $C u^{2 +} + 2 e^{-} \to C u$ in the half cell $P t_{s^{2 -} | C U S | C u}$ if $E_{C u^{2 +} | C u}^{⊖}$ is 0.34 and $K_{s p} o f C u S = 10^{- 35} ?$

0.34 V

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- 0.6925 V

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+ 0.6925 V

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- 0.66 V

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E_{R P}^{0}

{C u}^{2 +} + 2 e ⟶ C u

{P t}_{S^{2 -} / C u S / C u}

E_{{C u}^{2 +} / C u}

K_{s p}

C u S = 10^{- 35}

C u^{2 +} + e^{-} \to C u^{\oplus}

E^{\oplus} = 1.77 V

C u^{2 +} + 2 e^{-} \to C u

E^{⊖} = - 0.34

E^{⊖}

C u^{\oplus} + e^{-} \to C u

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15 V

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34 V

E^{o}

C u^{+} + e^{-} \to C u

C u^{+}

E^{o}

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34

E^{o}

C u^{+} + e^{-} \to C u

E

E^{\circ}

N i | N i^{2 +} | | C u^{2 +} | C u

N i^{2 +} + 2 e^{-} \to N i; E^{\circ} = - 0.25 v o l t

C u^{2 +} + 2 e^{-} \to C u; E^{\circ} = + 0.34 v o l t

[N i^{2 +}] = 1 M

[C u^{2 +}] = 10^{- 3} M)

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