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Application of Electrolysis

What is E R...

Question

What is $E_{R P}^{0}$ for the reaction : ${C u}^{2 +} + 2 e ⟶ C u$ in the half cell ${P t}_{S^{2 -} / C u S / C u}$ if $E_{{C u}^{2 +} / C u}$ is 0.34 V and $K_{s p}$ of $C u S = 10^{- 35}$ ?

A

0.34 V

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B

0.6925 V

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C

+0.6925 V

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D

0.66 V

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Solution

The correct option is C 0.6925 V
$E_{S^{2 -} / C u S / C u} = E_{{C u}^{2 +} / C u}^{0} + \frac{0.0591}{2} l o g k_{s p} C u S$
$= 0.34 + \frac{0.0591}{2} l o g 10^{- 35}$
$= - 0.6925 V$

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Similar questions

E_{r e d}^{⊖}

for the reaction;

C u^{2 +} + 2 e^{-} \to C u

in the half cell

P t_{s^{2 -} | C U S | C u}

E_{C u^{2 +} | C u}^{⊖}

K_{s p} o f C u S = 10^{- 35} ?

Q. E.M.F. of the cell reaction,

2 A g^{+} + C u ⟶ 2 A g + C u^{2 +}

E_{{C u}^{2 +} / C u}

E_{{A g}^{+} / A g}

Q. If for the following half-cell reactions :

C u^{2 +} + e^{-} \to C u^{\oplus}

E^{\oplus} = 1.77 V

C u^{2 +} + 2 e^{-} \to C u

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