What is electronic arrangement of metal atom-ion in octahedral complex with d 4 configuration- if -0- pairing energy-A- t2 g4 egcB- e g 4 t g -C- t2 g3 eg1D- t 2 g 2 e g 2

The correct option is C t^3_2g e^1_g Conceptual ...

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Standard XII

Chemistry

Introduction to p Block Elements

What is elect...

Question

What is electronic arrangement of metal atom/ion in octahedral complex with $d^{4}$ configuration, if $Δ_{0}$ < pairing energy.

t_{2 g}^{4} e_{g}^{\circ}

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e_{g}^{4} t_{g}^{\circ}

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t_{2 g}^{3} e_{g}^{1}

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t_{2 g}^{2} e_{g}^{2}

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Solution

The correct option is C $t_{2 g}^{3} e_{g}^{1}$

Conceptual

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Similar questions

Q. A metal ion

M^{n +}

having

d^{4}

valence electronic configuration combines with three bidentate ligands to form a complex compound. Assuming

△ a > p

:
(i) Write the electronic configuration of

d^{4}

ion.
(ii) What type of hybridisation will

M^{n +}

ion has?
(iii) Name the type of isomerism exhibited by this complex.

Q. What is meant by crystal field splitting energy ? On the basis of crystal field theory, write the electronic configuration of

d^{4}

in terms of

t_{2 g}

and

e_{g}

in an octahedral field when
(i)

Δ_{0} > P

(ii)

Δ_{0} < P

If $Δ_{\circ}$ > P (P = pairing energy; $Δ_{\circ}$ change in energy of octahedral complexes), the correct electronic configuration for $d^{4}$ system will be

Q. If

△_{0} < P,

the correct electronic configuration for

d^{4}

system will be -

Q. If

Δ_{0} < P

, the correct electronic configuration for

d^{4}

system will be:

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What is electronic arrangement of metal atom/ion in octahedral complex with d4 configuration, if Δ0 < pairing energy.

The correct option is C t32ge1g Conceptual

What is electronic arrangement of metal atom/ion in octahedral complex with $d^{4}$ configuration, if $Δ_{0}$ < pairing energy.

The correct option is C $t_{2 g}^{3} e_{g}^{1}$

Conceptual