What is $\frac{{\frac{3}{4}}^{7}}{{\frac{4}{3}}^{- 5}}$ ?

16/9

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9/16

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16/3

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3/16

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Solution

The correct option is B
9/16

$\frac{{\frac{3}{4}}^{7}}{{\frac{4}{3}}^{- 5}}$ = $\frac{{\frac{3}{4}}^{7}}{{\frac{3}{4}}^{5}}$ = ${(\frac{3}{4})}^{7 - 5}$ = $\frac{9}{16}$

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Similar questions

\frac{5 + \sqrt{3}}{7 - 4 \sqrt{3}} = 47 + 27 \sqrt{3}

$^{47} C_{4} + 5 \sum r = 1^{52 - r} C_{3}$ =

{(\frac{3}{4})}^{- 4} \times {(\frac{3}{4})}^{7}

^{47} C_{4} + \sum_{j = 1}^{5}^{52 - j} C_{3} =

{(\frac{2}{3})}^{4} \times {(\frac{2}{3})}^{6}

{(\frac{2}{7})}^{0}

{(\frac{3}{5})}^{7}

{[{(\frac{3}{4})}^{2}]}^{5}

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