What is -3-i-3-i6 equal to- where i-1-

The correct option is A 1 (√(3)+ i √(3) i×√(3)+i√(3)+i)^ 6 (√(3)+i)^12(3 1)^6 (√(3)+i)^12(2^6) (1+√(3)i2)^6 now, (√(3)i+12 = w^2) ...

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Properties of Conjugate of a Complex Number

What is √3+...

Question

What is ${(\frac{\sqrt{3} + i}{\sqrt{3} - i})}^{6}$ equal to, where $i = \sqrt{- 1} ?$

1

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\frac{1}{6}

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6

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2

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Solution

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Similar questions

z_{1} = \frac{2 \sqrt{3} + i 6 \sqrt{7}}{6 \sqrt{7} + i 2 \sqrt{3}}

z_{2} = \frac{\sqrt{11} + i 3 \sqrt{13}}{3 \sqrt{13} + i \sqrt{11}}

∣ ∣ ∣ \frac{1}{z_{1}} + \frac{1}{z_{2}} ∣ ∣ ∣

{⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \frac{sin \frac{π}{6} + i (1 - cos \frac{π}{6})}{sin \frac{π}{6} - i (1 - cos \frac{π}{6})} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦}^{3}

i = \sqrt{- 1}

\sqrt{- 1}, t h e n 1 + i^{2} + i^{3} - i^{6} + i^{8}

{[\frac{- 1 + i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 + i \sqrt{3}}{2}]}^{5} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{5} =

{[\frac{- 1 + i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 + i \sqrt{3}}{2}]}^{5} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{5} =

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