Question

What is $pH$ if $H_{2}S{O}_4$ is added in water $H_{2}S{O}_4$ = ${10}^{-2}m$

Answer 1

As there are two $H^{+}$ ions in $H_{2}S{O}_4$,

$\therefore \left[H^{+}\right]=2\times {10}^{-2}M$

$\therefore pH=-\log \left[H^{+}\right]=-\log (2\times {10}^{-2})\approx 1.7$