What is pH of 50 ml 0.1 (M) $N H_{4} O H$ and 50 ml 0.05 (M) HCI?
$p K_{b} = 4.73$

9.27

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9.37

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8.37

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9.47

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Solution

The correct option is A 9.27
$N H_{4} O H$ + HCl $\to$ $N H_{4} C l + H_{2} O$
5 2.5 Milli moles before reaction
2.5 0 Milli moles before reaction
Concentration of both $N H_{4} C l$ and $N H_{3} = 2.5 \times 10^{- 2} M$
Applying henderson's equation-2
$p O H = p K_{b} + l o g \frac{[S a l t]}{[B a s e]} = 4.73$
$p H = 14 - 4 .73 = 9.27$

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