Question

What is pressure on swimmer 10 m below the surface of a lake? Atmospheric pressure is

Answer 1

Given,

Pressure, $P=P_{atm}+\rho gh$

Where,

$h=$ Depth of water $=10m$

$\rho =$ Density of water $=1000kg{m}^{-3}$

$P_{atm}=$ Atmospheric pressure

$P=P_{atm}+1000\times 9.8\times 10=(P_{atm}+98000)pa$

Hence, pressure at depth$10m$is $(P_{atm}+98000)pa$