Question

What is the pressure on a swimmer 10 m below the surface of a lake?

Answer 1

Let atmospheric pressure $=P_o=1.05\times {10}^5$ Pa

Pressure $10$m below surface of lake,

$P=P_o+\rho gh$

$=1.05\times {10}^5+1000\times 9.8\times 10$

$-1.99\times {10}^{5}Pa$

$=2$ atm ($\rho \to$ Density of water $=1000$ kg$/m^3$, $g=9.8m/s^2$ $h\to$ Depth$=10$m).