What is the $20^{t h}$ term of the sequence defined by $a_{n} = (n - 1) (2 - n) (3 + n) ?$

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Solution

Finding $20^{t h}$ term.
Given, $a_{n} = (n - 1) (2 - n) (3 + n)$
Substituting $n = 20$ in $a_{n}$ , we get
$a_{20} = (20 - 1) (2 - 20) (3 + 20)$
$\Rightarrow a_{20} = 19 \times (- 18) \times 23$
$\Rightarrow a_{20} = - 7866$

Therefore, the $20^{t h}$ term of the given sequence is $- 7866$ .

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What is the 20th term of the sequence defined by an=(n−1)(2−n)(3+n)?

Finding 20th term. Given, an=(n−1)(2−n)(3+n) Substituting n=20 in an, we get a20=(20−1)(2−20)(3+20) ⇒a20=19×(−18)×23 ⇒a20=−7866 Therefore, the 20th term of the given sequence is −7866.

What is the $20^{t h}$ term of the sequence defined by $a_{n} = (n - 1) (2 - n) (3 + n) ?$

Finding $20^{t h}$ term.
Given, $a_{n} = (n - 1) (2 - n) (3 + n)$
Substituting $n = 20$ in $a_{n}$ , we get
$a_{20} = (20 - 1) (2 - 20) (3 + 20)$
$\Rightarrow a_{20} = 19 \times (- 18) \times 23$
$\Rightarrow a_{20} = - 7866$

Therefore, the $20^{t h}$ term of the given sequence is $- 7866$ .