Question

What is the absolute term for the quadratic equation $x+\frac{1}{3}=\frac{x^2}{2}-3$?

• A. $-17$
• B. $-18$
• C. $-19$
• D. $-20$

Answer 1

Answer: (D)

$-20$

Given, $x+\frac{1}{3}=\frac{x^2}{2}-3$
$\frac{3x+1}{3}=\frac{x^2-6}{2}$

$6x+2=3x^2-18=0$
$3x^2-6x-20=0$
The absolute term is $-20$.