Question

What is the actual volume occupied by water molecules present in $20c{m}^3$ of water ?

• A. $20c{m}^3$
• B. $10c{m}^3$
• C. $40c{m}^3$
• D. $24.89d{m}^3$

Answer 1

The correct option is D $24.89d{m}^3$

Density of water = 1 $g/cc$

Therefore 20 $c{m}^3$ weights 20 g of water molecules.

So number of moles of water $=\frac{20}{18}=1.11$ moles

1 mole occupies 22.4 L.

Therefore 1.11 moles occupies 24.89 L, i.e., 24.89 $d{m}^3$.