What is the angle $A B C$ formed by two set squares in the given image?

$45^{\circ}$

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$30^{\circ}$

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$120^{\circ}$

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$90^{\circ}$

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Solution

The correct option is C
$120^{\circ}$

The angles of one of the set square are $45^{\circ}, 90^{\circ}, 45^{\circ}$ .

The angles of one of the set square are $30^{\circ}, 90^{\circ}, 60^{\circ}$ .

The angle in the figure is the sum of $30^{\circ}$ and $90^{\circ}$ . So, the value of the angle is $120^{\circ}$ .

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Similar questions

In the given figure, $∠ A O B = 90^{\circ} a n d ∠ A B C = 30^{\circ} . T h e n, ∠ C A O = ?$

(a) $30^{\circ}$

(b) $45^{\circ}$

(d) $90^{\circ}$

In the given figure, if the angle between two radii of a circle is $120^{\circ}$ , then find $∠$ PAO.

△ A B C

∠ A + ∠ C

If $2 ∠ A = 3 ∠ B = 6 ∠ C$ in a $Δ A B C$ , then $∠ A$ , $∠ B$ , $∠ C$ are

∠

∠

∠

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