Question

What is the area of a triangle with base 4.8 cm and height 3.6 cm ?

Answer 1

Given base of triangle $=4.8cm$

height of triangle$=3.6cm$

area = $\frac{1}{2}|base\times height|$

$=\frac{1}{2}\times 4.8\times 3.6=2.4\times 3.6$

[area = $8.64c{m}^2$]