What is the average kinetic energy per atom of each gas ?

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Solution

Since both Helium and Neon are monoatomic gases, degree of freedom for each gas is f=3. From ideal gas theory, average kinetic energy is equal to the thermal energy. Hence

$K E = \frac{f}{2} k T = \frac{3}{2} (1.38 X 10^{- 23}) (300) = 6.21 X 10^{- 21} J / a t o m$

Answer is $6.21 X 10^{- 21} J$

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What is the average kinetic energy per atom of each gas ?

Since both Helium and Neon are monoatomic gases, degree of freedom for each gas is f=3. From ideal gas theory, average kinetic energy is equal to the thermal energy. HenceKE=f2kT=32(1.38X10−23)(300)=6.21X10−21J/atomAnswer is 6.21X10−21J

Since both Helium and Neon are monoatomic gases, degree of freedom for each gas is f=3. From ideal gas theory, average kinetic energy is equal to the thermal energy. Hence

$K E = \frac{f}{2} k T = \frac{3}{2} (1.38 X 10^{- 23}) (300) = 6.21 X 10^{- 21} J / a t o m$

Answer is $6.21 X 10^{- 21} J$