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Question

What is the average translational kinetic energy of a gas molecule at 500 K?

A
1035×1023 J
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B
750×1023 J
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C
1725×1023 J
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D
1150×1023 J
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Solution

The correct option is A 1035×1023 J
Average kinetic energy, E=32KT
E=32×(1.38×1023)×500
E=1035×1023 J

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