Question

What is the average translational kinetic energy of a gas molecule at $500\text{K}$?

• A. $1035\times {10}^{-23}\text{J}$
• B. $750\times {10}^{-23}\text{J}$
• C. $1725\times {10}^{-23}\text{J}$
• D. $1150\times {10}^{-23}\text{J}$

Answer 1

The correct option is A $1035\times {10}^{-23}\text{J}$

Average kinetic energy, $E=\frac{3}{2}KT$
$E=\frac{3}{2}\times (1.38\times {10}^{-23})\times 500$
$E=1035\times {10}^{-23}\text{J}$