Question

What is the change in the volume of 1.0 L kerosene, when it is subjected to an extra pressure of $2.0\times {10}^{5}N{m}^{-2}$ from the following data? Density of kerosene = 800 kg m${}^{-3}$ and speed of sound in kerosene = 1330 ms${}^{-1}$

• A. 0.97 cm${}^{-3}$
• B. 0.66 cm${}^{-3}$
• C. 0.15 cm${}^{-3}$
• D. 0.59 cm${}^{-3}$

Answer 1

Answer: (C)

0.15 cm${}^{-3}$

Speed of sound, $v=\sqrt{\frac{K}{\rho }}$

$⟹K=v^2\rho$ $={1330}^2\times 800N{m}^2$

Also we know, $K=\frac{P}{\Delta V/V}$

$⟹\Delta V=0.15c{m}^{-3}$