What is the charge on the complex $[Cr {(C_{2} O_{2})}_{2} {(H_{2} O)}_{2}]$ formed by $Cr(III)$ ?

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Solution

The correct option is A 3
$[C r (C_{2} O_{2})_{2} (H_{2} O)_{2}]; H_{2} O \to$ Neutral Ligand.
$C_{2} O_{2} \Rightarrow C O - C O$ Neutral
$[C r^{3 +} (C_{2} O_{2})_{2}^{o} (H_{2} O)_{2}^{o}]^{3 +}$
Charge $= + 3$

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