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Compound Ratio

What is the c...

Question

What is the compounded ratio of $9 : 27$ and $4 : 12$

3 : 11

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2 : 11

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1 : 9

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2 : 9

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Solution

The correct option is C $1 : 9$
By the defination of compound ratio $9 : 27$ and $4 : 12$ can be expressed as
$\frac{9}{27} \times \frac{4}{12} = \frac{1}{9}$
Hence $1 : 9$

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Similar questions

Name the property of multiplication illustrated by each of the following statements :

(i) $\frac{- 15}{8} \times \frac{- 12}{7} = \frac{- 12}{7} \times \frac{- 15}{8}$

(ii) $(\frac{- 2}{3} \times \frac{7}{9}) \times \frac{- 9}{5} = \frac{- 2}{3} \times (\frac{7}{9} \times \frac{- 9}{5})$

(iii) $\frac{- 3}{4} \times (\frac{- 3}{4} \times \frac{- 5}{6}) + (\frac{- 3}{4} \times \frac{7}{8})$

(iv) $\frac{- 16}{9} \times 1 = 1 \times \frac{- 16}{9} = \frac{- 16}{9}$

(v) $\frac{- 11}{15} \times \frac{15}{- 11} = \frac{15}{- 11} \times \frac{- 11}{15} = 1$

(vi) $\frac{- 7}{5} \times 0 = 0$

Simplify:

$(\frac{2}{3} + \frac{4}{9})$ of $\frac{3}{5} \div 1 \frac{2}{3} \times 1 \frac{1}{4} - \frac{1}{3}$

\frac{9 π}{8} - \frac{9}{4} {sin}^{- 1} (\frac{1}{3}) = \frac{9}{4} {sin}^{- 1} (\frac{2 \sqrt{2}}{3})

H C F

(2 \times 3 \times 7 \times 9)

, (2 \times 3 \times 9 \times 11)

(2 \times 3 \times 4 \times 5) ?

\frac{- 3}{11}, \frac{- 1}{4}

\frac{5}{8}

\frac{- 5}{9}, \frac{- 7}{12}

\frac{11}{18}

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