What is the concentration of a solution of 2,000 grams of water in which 684 grams of sucrose, C12H22O11 is dissolved?
A
25 molar
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.5 molal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1 molal
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5 molar
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
1 molar
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 1 molal The concentration of a solution of 2,000 grams of water in which 684 grams of sucrose, C12H22O11 is dissolved is 1 molal. Molar mass of sucrose is 342 g/mol. 684 g of sucrose corresponds to 684342=2 moles. Mass of water is 2000 g or 2 kg. The molality of solution is the number of moles of sucrose present per kg of water. It is 2mol2kg=1m