What is the conjugate hyperbola of the hyperbola x2a2−y2b2=1
A
x2a2+y2b2=1
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B
x2a2−y2b2=1
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C
x2a2−y2b2=−1
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D
−x2a2−y2b2=1
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Solution
The correct option is C
x2a2−y2b2=−1
We say hyperbola A is the conjugate hyperbola of the hyperbola B, if the transverse axis of A is the conjugate axis of the hyperbola B and vice versa. For the standard hyperbola x2a2−y2b2=1,
the equation of conjugate hyperbola is given by x2a2−y2b2=−1