What is the coordination number of Cr in $K_{3} C r (o x)_{3} ?$

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Solution

The correct option is D 3
$C o o r d i n a t i o n n u m b e r$ is defined as the number of atoms that immediately surround the central metal atom in a complex.

In complex $K_{3} [C r (o x)_{3}]$ , central metal ion is $C r$ and three oxalate ion surround it.

Oxalate $(C_{2} O_{2}^{- 2})$ is a bidentate ligand and donate two lone pair of electrons to the metal atom.

$C o o r d i n a t i o n n u m b e r$ = (number ligands attached to central metal ion x denticity of ligand)

Therefore, the coordination number of Cr in $K_{3} [C r (o x)_{3}]$ is 6 (Ox $= 3 \times 2$ )

Hence the correct option is (A).

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