Question

What is the correct formulation of Hardy-Weinberg law?

• A. $p^2+2pq+q^2=1$
• B. $p^2+pq+q^2=0$
• C. $p^2+pq+q^2=1$
• D. $p^2+2pq+q^2=0$

Answer 1

The correct option is A $p^2+2pq+q^2=1$

The Hardy-Weinberg equation used to determine genotype frequencies is:

$p^2+2pq+q^2=1$.

Where $p^2$ represents the frequency of the homozygous dominant genotype.

$2pq$ represents the frequency of the heterozygous genotype.

$q^2$ represents the frequency of the homozygous recessive genotype.

Hence the correct option is
a. $p^2+2pq+q^2=1$