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Question

What is the correct IUPAC name of the compound?

CH2=CHCH2C CH?


A

1, 4-Pentenyne

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B

Pent-1-en-4-yne

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C

Pent-1-yn-4-ene

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D

1, 4-Pentynene

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Solution

The correct option is B

Pent-1-en-4-yne


While naming, the double bond gets a lower number than the trible bind.

C1H2=C2HC3H2C4 C5H

Wort root=pent

Pent-1-en-4-yne

Not

4-Penten-1-yne

Because, if there is a choice in numbering, the double bond is always given performance over the trible

bond


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