What is the correct IUPAC name of the compound?
CH2=CH−CH2−C≡ CH?
Pent-1-en-4-yne
While naming, the double bond gets a lower number than the trible bind.
C1H2=C2H−C3H2−C4≡ C5H
Wort root=pent
Pent-1-en-4-yne
Not
4-Penten-1-yne
Because, if there is a choice in numbering, the double bond is always given performance over the trible
bond