What is the correct $I U P A C$ name of the following compound?

$C H_{2} = C H - C H_{2} - C \equiv C H$

Pent-

1

-en-

4

-yne

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Pent-

4

-yn-

1

-ene

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Pent-

4

-en-

1

-yne

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Pent-

1

-yn-

4

-ene

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Solution

The correct option is A Pent- $1$ -en- $4$ -yne
In the given compound,
a. The carbon backbone chain contains total 5 carbon atoms so the root word will be "pent".
b. There are both double and triple bond present in the molecule, hence double bond will get the priority over the triple bond and backbone numbering will be done in such a way that the double bond will be assigned the minimum number.
c. "ene" comes before "yne" in the name
So the I.U.P.A.C name of the compound will be Pent-1-en-4-yne. So the correct option is A

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