What is the correct order of acidic strength of oxides of nitrogen :

N_{2} O > N O > N_{2} O_{3} > N_{2} O_{5}

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N_{2} O_{3} > N O > N_{2} O > N_{2} O_{5}

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N_{2} O > N_{2} O_{5} > N_{2} O_{3} > N O

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N_{2} O_{5} > N_{2} O_{3} > N O > N_{2} O

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Solution

The correct option is D $N_{2} O_{5} > N_{2} O_{3} > N O > N_{2} O$
Oxidation no of N in various oxides are as follows:
$N_{2} O$ - +1
$N O$ - +2
$N_{2} O_{3}$ - +3
$N_{2} O_{5}$ - +5
Oxides in the higher oxidation state of an element are more acidic than that of the lower oxidation state. Hence the acidic strength of oxides of nitrogen increases from $N_{2} O_{3}$ to $N_{2} O_{5}$

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