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Byju's Answer
Standard XII
Chemistry
Nomenclature
What is the c...
Question
What is the correct structure of
3
-Bromoprop-
1
-ene?
A
C
H
3
−
C
B
r
=
C
H
2
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B
B
r
−
C
H
=
C
=
C
H
2
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C
B
r
−
C
H
2
=
C
H
−
C
H
2
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D
B
r
−
C
H
2
−
C
H
=
C
H
2
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Solution
The correct option is
B
B
r
−
C
H
2
−
C
H
=
C
H
2
The structure of the 3-Bromoprop-1-ene can be given as follow:
B
r
−
C
H
2
−
C
H
=
C
H
2
In this compound, according to IUPAC rule, the double bond is given preference over the bromo group.
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1
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(d)
C
H
3
−
C
H
2
−
C
H
2
−
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r
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H
−
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H
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a
n
d
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H
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(
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Q.
The decreasing order of rate of
S
N
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is :
(I)
B
r
−
C
H
2
−
C
H
2
−
B
r
(II)
N
=
C
−
C
H
2
−
B
r
(III)
C
H
3
−
C
|
B
r
H
−
C
H
3
(IV)
C
H
3
−
C
H
2
−
B
r
Q.
A)
C
H
3
−
C
H
2
−
⊕
C
H
2
B)
C
H
3
−
C
H
|
F
−
⊕
C
H
2
C)
C
H
3
−
C
H
|
B
r
−
⊕
C
H
2
D)
C
H
3
−
C
H
|
C
l
−
⊕
C
H
2
Arrange the following carbocations in decreasing order of their stability:
Q.
The decreasing order of rate of
S
N
2
is
(I)
C
l
−
C
H
2
−
C
H
2
−
B
r
(II)
N
≡
C
−
C
H
2
−
B
r
(III)
C
H
3
−
C
H
|
B
r
−
C
H
3
(IV)
C
H
3
−
C
H
2
−
B
r
Q.
CH
3
−
CH
2
−
Br
+
CH
3
−
CH
2
−
Br
Na
/
dry
ether
−
−−−−−−−
→
The
product
/
s
formed
are