What is the correct value of Bohr magneton?

8.99 x

10^{- 24} A m^{2}

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9.27 x

10^{- 24} A m^{2}

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5.66 x

10^{- 24} A m^{2}

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9.27 x

10^{- 28} A m^{2}

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Solution

The correct option is C 9.27 x $10^{- 24} A m^{2}$
Bohr Magnetron
$(μ_{l})_{m i n} = μ_{s} = \frac{e}{4 π m_{e}} h$
Here, e = 1.6 X $10^{- 19}$ C, h = 6.64 X $10^{- 34} J$ s
$m_{e}$ = 9.1 X $10^{- 31}$ kg
$∴ μ_{B}$ = $\frac{1.60 \times 10^{- 19} \times 6.64 \times 10^{- 34}}{4 \times 3.14 \times 9.1 \times 10^{- 31}}$ = 9.27 X $10^{- 24}$ A $m^{2}$

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What is the correct value of Bohr magneton?

The correct option is C 9.27 x 10−24Am2Bohr Magnetron(μl)min=μs=e4πmehHere, e = 1.6 X 10−19 C, h = 6.64 X 10−34J sme = 9.1 X 10−31 kg∴μB = 1.60×10−19×6.64×10−344×3.14×9.1×10−31 = 9.27 X 10−24Am2