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Degree of a Polynomial

What is the d...

Question

What is the degree of the polynomial $p (x) = 5 x^{3} - 8 x^{2} + 4 x ?$

3

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Solution

The correct option is A $3$
The polynomial $a x^{3} + b x^{2} + c x + d = 0$ is in standard form.
On comparing $5 x^{3} - 8 x^{2} + 4 x$ with the standard form, the power of the first term is $3$ , the power of the second term is $2$ and the power of the third term is $1$ . Since the polynomial has the largest exponent, that is $3$ which is the degree of the polynomial.

Hence, the degree of the polynomial is $3$

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Similar questions

n

{[\frac{2}{\sqrt{5 x^{3} + 1} - \sqrt{5 x^{3} - 1}}]}^{8} + {[\frac{2}{\sqrt{5 x^{3} + 1} + \sqrt{5 x^{3} - 1}}]}^{8}

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p (x) : p (x) = a x^{4} + b x^{3} + c x^{2} + d x + e

\frac{a}{b} = 0 & b \neq 0

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p (y) = \frac{5}{2} y^{2} + 1

p (x) = 2 x^{3} - x^{2} + 4 x + 1

p (x) = 3 x^{2}

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p (x) = - 7

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p (x) = 5 x^{2} - 3 x + 2

p (x) = 4 x

p (x) = \frac{3}{2}

p (x) = \sqrt{3} x + 1

p (y) = y^{3} + 3 y

n

{[\frac{2}{\sqrt{5 x^{3} + 1} - \sqrt{5 x^{3} - 1}}]}^{8} + {[\frac{2}{\sqrt{5 x^{3} + 1} + \sqrt{5 x^{3} - 1}}]}^{8}

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