wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the density of wet air with 75% relative humidity at 1 atm and 300 K? Given vapour pressure of H2O is 30 torr and average molar mass of air is 29gmol−

A
1.815 g/L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.165 g/L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.365 g/L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.165 g/L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1.165 g/L
% Relative humidity = Partial pressure of H2O Relative pressure of H2O×100
75=PH2O 30×100P˙H2O=22.5torr
% of H2O vapour in air=225760×100=2096
molar mass of wet air
=29×97.04+2.96×18100=28.67
density of wet air =PMRT=1×28.670.0821×300
=1.1659/L
Correct Answer - B

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Liquids in Liquids and Raoult's Law
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon