What is the difference between the average number of candidates who appeared for CS in the year 2007 and 2008 and average number of candidates who appeared for ES in the same years?

38400

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24400

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26000

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26400

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24000

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Solution

The correct option is C 26000
The average number of candidates who appeared for CS in the year 2007 and 2008 $= \frac{58000 + 60000}{2} = \frac{118000}{2} = 59000$
The average number of candidates who appeared for ES in the year 2007 and 2008 $= \frac{30000 + 36000}{2} = \frac{66000}{2} = 33000$
$∴$ required difference $= (59000 - 33000) = 26000$

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What is the difference between the average number of candidates who appeared for CS in the year 2007 and 2008 and average number of candidates who appeared for ES in the same years?

The correct option is C 26000The average number of candidates who appeared for CS in the year 2007 and 2008 =58000+600002=1180002=59000 The average number of candidates who appeared for ES in the year 2007 and 2008 =30000+360002=660002=33000 ∴ required difference =(59000−33000)=26000