Resistance of metal (or conductor) increases with increases in temperature and vice-versa.
Given : Ro=3Ω at To=0oC
Also, restsiance at T1=100oC is R1=3.75Ω
Using R1=Ro(1+αΔT)
Here, ΔT=T1−To=100−0=100oC
Or 3.75=3(1+α×100)
⟹ α=2.5×10−3/oC
GIven : R2=3.15Ω
Using R2=Ro(1+αΔT)
Here, ΔT=T2−To=T2−0=T2
Or 3.15=3(1+2.5×10−3T2)
Or 2.5×10−3T2=0.05
⟹ T2=20oC