Question

What is the emitter current if $I_B=20\mu A$ and $\beta =100$ ?

• A. $2.02mA$
• B. $2.00mA$
• C. $1.01mA$
• D. $120mA$

Answer 1

The correct option is A $2.02mA$

The common emitter configuration can be shown as:


We know $\beta =\frac{I_C}{I_B}$
$\Rightarrow I_C=\beta \times I_B$
$=100\times 20\times {10}^{-6}A$
$=2\times {10}^{-3}A$
and
$I_E=I_B+I_C$
$=20\times {10}^{-6}+2\times {10}^{-3}$
$=2.02\times {10}^{-3}A$
$=2.02mA$