What is the empirical formula of the hydrocarbon $(C_{x} H_{y})$ that produced the mixture of products in the diagram after a combustion reaction?

C H_{4}

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C_{2} H_{8}

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C_{3} H_{4}

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C H_{2}

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Solution

The correct option is A $C H_{4}$
Given, products of reaction are $2 C O_{2}, 4 H_{2} O$
So, the products are $2 C O_{2}, + 4 H_{2} O$
So, the reactants has 2 carbons and 8 hydrogens.
So, the molecular formula $C_{2} H_{8}$
So, the empirical formula $C H_{4} = C : H = 1 : 4$

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