What is the empirical formula of vanadium oxide, if 2.74g of the metal oxide contains 1.53g of metal?
A
V2O3
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B
VO
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C
V2O5
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D
V2O7
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Solution
The correct option is CV2O5 Metal oxide = 2.74 g;weight of V=1.53g %ofV=1.532.74×100=55.83 Thus,%ofO=100−55.83=44.17 Number of moles of V=55.8352=1.1 Number of moles ofO=44.1716=2.76 Simplest ratio of V and O=1:2.5or2:5 Hence, the empirical formula=V2O5