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Question

What is the empirical formula of vandium oxide, if 2.73g of the metal oxide contains 1.53 g of metal?

[Given atomic mass of V=51]

A
V2O3
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B
VO
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C
V2O5
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D
V2O7
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Solution

The correct option is C V2O5
metal oxide =2.73gm
metal =1.53gm
oxygen =1.20gm
% of metal =1.532.73×100%=55.84%
% of oxygen =1.202.73×100%=44.16%
metal :- 1.53 males =1.5351=0.03 simplest ration 0.030.03=1
oxygen :1.20 moles =1.2016=0.075 0.0730.03=2.5
empirical formula =V2O5

1165261_1033973_ans_14ef53128acb42d28911d110ec2aa686.jpeg

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