Question

What is the energy change ($\Delta G^0$) when 1.0 mole of water at ${100}^{0}C$ and 1 atm pressure is converted into steam at ${100}^{0}C$ and 1 atm

• A. 80 cal
• B. 540 cal
• C. 620 cal
• D. zero

Answer 1

The correct option is D zero

Since water and vapour are in equilibrium and as we know
At equilibrium, ($\Delta G^0$)=0. Hence correct answer is zero.