Question

what is the equation of line passing through point(1,2) and perpendicular to 3x+4y+5=

Answer 1

Dear Student,

Slope of 3x+4y+5 = 0 is = -3/4.

Slope of a line perpendicular to 3x+4y-5=0

will be = 4/3.

eq. of required line is:-
$$\begin{gathered} y-2=\frac{4}{3}(x-1) \\ 3y-6=4x-4 \\ 4x-3y+2=0 \end{gathered}$$

Regards,