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Question

What is the equivalent mass of HCl in the given reaction?


2KMnO4+16 HCl2KCl+2MnCl2+5Cl2+8H2O


A
44.2
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B
36.5
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C
58.4
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D
none of these
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Solution

The correct option is C 58.4

As only 16 moles of Cl ions undergoes oxidation,(5Cl2 is product formed)
n - factor of HCl will be =1016=58 (N-factor of an acid is its basicity, in 16 moles of HCl, 10 moles of HCl is consumed)
Equivalent weight of HCl =Molar Massn - factor


Equivalent weight of HCl =36.5(58)=8×36.55=58.4


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