What is the equivalent mass of $I O_{4}^{-}$ when it is converted into $I_{2}$ in acid medium

\frac{M}{6}

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\frac{M}{7}

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\frac{M}{5}

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\frac{M}{4}

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None of these

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Solution

The correct option is B $\frac{M}{7}$
Equivalent mass
$= \frac{M o l e c u l a r w e i g h t}{C h a n g e i n o x i d a t i o n n u m b e r p e r m o l e}$
Suppose molecular weight is M
Oxidation number of $I_{2} i n I O_{4}^{-}$ in
Acidic medium i.e., $I \times (- 8) + I e^{-} = + 7$
So eq. wt. $\frac{M}{7}$ .

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