Question

What is the equivalent weight of silver nitrate?

Answer 1

Step1. Formula for the equivalent weight

$\text{Equivalent weight =}\frac{\text{Molecular weight}}{\text{Total charge on positive ion}}$

Step2. Chemical equation for the formation of silver nitrate

${\text{Ag}}^{\text{+}}{\text{+NO}}_3^{-}{\text{→AgNO}}_{\text{3}}$

Step3. Equivalent weight of Silver nitrate

• Molecular weight of Silver nitrate is $169.87{\text{g mol}}^{-1}$.

$$\begin{gathered} \text{Equivalent weight =}\frac{{\text{169.87 g mol}}^{\text{-1}}}{1} \\ \text{=169.87}\text{g}{\mathrm{mol}}^{\text{-1}} \\ =169.87\text{g}{\text{eq}}^{\text{-1}} \end{gathered}$$

Hence, the equivalent weight of Silver nitrate is is ${\text{169.87 g eq}}^{-1}$.