What is the factorization of $x^{2} - 5 x + 6$ ?

(x-2) (x-3)

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(x-1) (x+5)

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(x-6) (x+1)

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(x+5) (x-3)

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Solution

The correct option is A
(x-2) (x-3)

$x^{2} - 5 x + 6$

= $x^{2} - 2 x - 3 x + 6$

= x(x-2) - 3(x-2)

= (x-2) (x-3)

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Similar questions

x^{2} - 5 x - 6

:

x^{2} + 5 x + 6 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 5 x - 6 = 0

x^{2} - 5 x - 6 = 0

According to factor theorem, x-6 is the factor of $x^{2} - 5 x - 6$

x^{2} + 5 x + 6

x^{2} - 5 x + 6

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