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Question

What is the formula of a compound in which the element Y forms hcp lattice and atoms of X occupy (23)rd of tetrahedral voids?

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Solution

Suppose the number of atoms Y in hcp lattice = n. As the number of tetrahedral voids is double the number of atoms in close packing, the number of tetrahedral voids = 2n. As atoms X occupy (23)rd of the tetrahedral voids, the number of atoms X in the lattice :

23×2n=4n3

Ratio of X:Y=4n3:n=43:1=4:3

Hence, the formula of the compound is X4Y3.


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