What is the free energy change, $^{'} Δ G^{'}$ When 1.0 mole of water at 100 $^{0}$ C and 1atm pressure is converted into steam at 100 $^{0}$ C and 1atm pressure

Q. What is the free energy change

(△ G)

when 1.0 mole of water at

100^{o} C

and 1 atmospheric pressure is converted into steam at

100^{o} C

and 1 atmospheric pressure?

Q. What is the free energy change

△ G

, when

1.0

mole of water at

100^{o} C

and

1

atm pressure is converted steam at

100^{o} C

and

1

atm pressure:-

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What is the free energy change (ΔG) when 1.0 mole of water at 100oC and 1atm pressure is converted into steam at 100oC and 1atm pressure?

The correct option is D zero△G=?1 mole of water at 100℃ and 1 atm→Steam at 100℃ at 1 atmn=1T1=373KP1=1atmT2=373KP2=1atm△G=nRTln(P2P1)=nRTln(1)=0(ln1=0)

What is the free energy change $(Δ G)$ when $1.0$ mole of water at $100^{o} C$ and $1 a t m$ pressure is converted into steam at $100^{o} C$ and $1 a t m$ pressure?

The correct option is D zero
$△ G = ?$
1 mole of water at 100℃ and 1 atm $\to$ Steam at 100℃ at 1 atm
$n = 1 T_{1} = 373 K P_{1} = 1 a t m T_{2} = 373 K P_{2} = 1 a t m △ G = n R T l n (\frac{P_{2}}{P_{1}}) = n R T l n (1) = 0 (l n 1 = 0)$